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Example text
Each incident wave train such as A (Fig. 2) entering the interferometer is divided into two wave trains by the action of the beam-divider G. Let us adjust the difference between the two paths (1) and (2) so that it is greater than the length of the wave trains. When the wave train A; travelling in path (1) reaches P, the other is at A; if the mirror M, is the one which has been moved further away.
Each incident wave train such as A (Fig. 2) entering the interferometer is divided into two wave trains by the action of the beam-divider G. Let us adjust the difference between the two paths (1) and (2) so that it is greater than the length of the wave trains. When the wave train A; travelling in path (1) reaches P, the other is at A; if the mirror M, is the one which has been moved further away.
14). 16 represent F ( [ ) and f (u) as 5, tends to infinity. 17) The Fourier Transformation has a spectrum (Fig. 16) tend to ,c 5,/2 and 5,/2. 20 represent F ( 0 and f (v) for this case. results can be interpreted as follows: if F(C) represents the variation in amplitude on the wave surface (one-dimensional phenomena), the spectra, that is the diffraction patterns, have an amplitude given by f (v). 22) the amplitude at a point in the diffraction pattern is given by : Let us multiply the dimensions of the aperture in the directions Cq and Cc by m and n.